对android子菜单(SubMenu)的ContextMenuInfo返回空值的处理方法，

对android子菜单(SubMenu)的ContextMenuInfo返回空值的处理方法，

在列表页面（ListView）的弹出菜单中，有的时候我们需要用到子菜单，今天在使用的过程中发现，当我们需要获取ContextMenuInfo并取 得一些列表项(list Item)信息，当菜单为子菜单的时候，调用item.getMenuInfo()返回空值null。如下所示：

1.[Java]代码

@Override
public void onCreateContextMenu(ContextMenu menu, View v,
		ContextMenuInfo menuInfo) {
	menu.setHeaderTitle("操作");
	menu.add(0, VIEW_ID, 0, "查看全文");
	menu.add(0, DELETE_ID, 0, "删除");
	SubMenu submenu = menu.addSubMenu(1,SHARE,0,"分享");
   	submenu.add(2,SHARE1,0,"短信分享");
   	submenu.add(2,SHARE2,0,"Gmail分享");
	super.onCreateContextMenu(menu, v, menuInfo);
}

@Override
public boolean onContextItemSelected(MenuItem item) {
	AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
	RSSItem rssItem = (RSSItem) getListAdapter().getItem(info.position);
}

2.解决办法

private AdapterContextMenuInfo selectedMenuInfo = null; 

@Override
public void onCreateContextMenu(ContextMenu menu, View v,
		ContextMenuInfo menuInfo) {
	menu.setHeaderTitle("操作");
	menu.add(0, VIEW_ID, 0, "查看全文");
	menu.add(0, DELETE_ID, 0, "删除");
	SubMenu submenu = menu.addSubMenu(1,SHARE,0,"分享");
   	submenu.add(2,SHARE1,0,"短信分享");
   	submenu.add(2,SHARE2,0,"Gmail分享");
	selectedMenuInfo = (AdapterContextMenuInfo) menuInfo;
	super.onCreateContextMenu(menu, v, menuInfo);
}

@Override
public boolean onContextItemSelected(MenuItem item) {
	AdapterContextMenuInfo info = (AdapterContextMenuInfo) item.getMenuInfo();
	if(info == null){
           info = selectedMenuInfo;
       }
	RSSItem rssItem = (RSSItem) getListAdapter().getItem(info.position);
}